Algebra Practice Test 2025 – 400 Free Practice Questions to Pass the Exam

Question: 1 / 400

What are the values of x and y in the system of equations: 2x + 3y = 6 and 4x - y = 5?

x = 1, y = 2

x = 2, y = 0

To determine the values of x and y in the given system of equations, we can use either substitution or elimination methods. Here, let's use the substitution method for clarity.

First, we can solve one of the equations for one variable. Let's take the second equation, \( 4x - y = 5 \), and solve for y:

\[ y = 4x - 5. \]

Next, we can substitute this expression for y into the first equation, \( 2x + 3y = 6 \):

\[ 2x + 3(4x - 5) = 6. \]

Expanding this gives:

\[ 2x + 12x - 15 = 6. \]

Combining like terms results in:

\[ 14x - 15 = 6. \]

Adding 15 to both sides yields:

\[ 14x = 21. \]

Dividing both sides by 14 gives:

\[ x = \frac{21}{14} = \frac{3}{2}. \]

Now that we have a value for x, we can substitute \( x = \frac{3}{2} \) back into our expression for y:

\[ y

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x = 0, y = 2

x = 3, y = -1

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